第一种：利用线程延时实现：
private int mBackKeyPressedTimes = 0;
@Override
public void onBackPressed() {
if (mBackKeyPressedTimes == 0) {
Toast.makeText(this, "再按一次退出程序 ", Toast.LENGTH_SHORT).show();
mBackKeyPressedTimes = 1;
new Thread() {
@Override
public void run() {
try {
Thread.sleep(2000);
} catch (InterruptedException e) {
e.printStackTrace();
} finally {
mBackKeyPressedTimes = 0;
}
}
}.start();
return;
else{
this.activity.finish();
}
}
super.onBackPressed();
}
第二种：利用计算时间差实现 (个人觉得这种方式较为简单，而且不容易发生异常，代码较为安全)
private long exitTime = 0;
public void ExitApp()
{
if ((System.currentTimeMillis() - exitTime) > 2000)
{
Toast.makeText(this.activity, "再按一次退出程序", Toast.LENGTH_SHORT).show();
exitTime = System.currentTimeMillis();
} else
{
this.activity.finish();
}
}
本文作者:fuweiping 来源:CSDN
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